修改频闪问题
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@ -41,5 +41,5 @@ export const createFile = (data: any) => {
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// 上传文件
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// 上传文件
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export const updateFile = (data: any) => {
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export const updateFile = (data: any) => {
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return request.upload({ url: '/infra/file/upload', data })
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return request.upload({ url: '/infra/file/businessUploadFile', data })
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}
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}
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@ -7,9 +7,11 @@ import axios from 'axios'
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* 获得上传 URL
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* 获得上传 URL
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*/
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*/
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export const getUploadUrl = (): string => {
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export const getUploadUrl = (): string => {
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return import.meta.env.VITE_BASE_URL + import.meta.env.VITE_API_URL + '/infra/file/upload'
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// return import.meta.env.VITE_BASE_URL + import.meta.env.VITE_API_URL + '/infra/file/upload'
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return import.meta.env.VITE_BASE_URL + import.meta.env.VITE_API_URL + '/infra/file/businessUploadFile'
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}
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}
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export const useUpload = () => {
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export const useUpload = () => {
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// 后端上传地址
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// 后端上传地址
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const uploadUrl = getUploadUrl()
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const uploadUrl = getUploadUrl()
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@ -763,16 +763,10 @@ const linkWebSocket = (url) => {
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data: JSON.parse(data[key])
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data: JSON.parse(data[key])
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})
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})
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}
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}
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console.log('=====',data)
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console.log('=====',dataList)
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dataList.forEach((item) => {
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// console.log('=====', item.data.pose2d.robotNo)
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// testCarList.value = JSON.parse(JSON.stringify(dataList))
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if(item.data.pose2d.robotNo == "zn002" ){
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testCarList.value = mergeCarArrays(testCarList.value, dataList)
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console.log(item)
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console.log('x',item.data.pose2d.x)
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console.log('y',item.data.pose2d.y)
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}
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})
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testCarList.value = dataList
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computedRatio()
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computedRatio()
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}
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}
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//告警信息
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//告警信息
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@ -820,6 +814,38 @@ const linkWebSocket = (url) => {
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})
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})
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}
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}
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}
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}
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const mergeCarArrays =(arr1, arr2) => {
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const result = [];
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const macAddressSet = new Set();
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// 先处理第一个数组中原本就有的元素,进行更新或保留
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for (const item1 of arr1) {
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const macAddress1 = item1.macAddress;
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macAddressSet.add(macAddress1);
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let foundInSecond = false;
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for (const item2 of arr2) {
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const macAddress2 = item2.macAddress;
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if (macAddress1 === macAddress2) {
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foundInSecond = true;
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// 更新pose2d信息
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item1.data.pose2d = item2.data.pose2d;
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result.push(item1);
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break;
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}
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}
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if (!foundInSecond) {
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// 如果没在第二个数组中找到,就不添加到结果中,相当于删除
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continue;
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}
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}
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// 再处理第二个数组中存在但第一个数组中不存在的元素,添加到结果中
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for (const item2 of arr2) {
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const macAddress2 = item2.macAddress;
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if (!macAddressSet.has(macAddress2)) {
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result.push(item2);
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}
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}
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return result;
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}
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const setIsSelect = (arr1, arr2) => {
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const setIsSelect = (arr1, arr2) => {
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for (let i = 0; i < arr1.length; i++) {
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for (let i = 0; i < arr1.length; i++) {
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const element = arr1[i]
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const element = arr1[i]
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